Reply to "OUtdoor hitting facility"

shortstopmom1,000+ posts

quote:
T=W*L/(8*h) where

T = tension
W = total weight of cable and netting for one cable
L = span of the cable
h = sag at the center of the cable

So for a single cable, assuming the cable and netting weight 115 lbs, the span is 70 feet, and the cable is allowed to sag 4" (0.3333 feet), the tension is 3019 lbs. If you have three parallel cables, the load on each wall holding the cable anchors would be 9000 lbs. Obviously the cable needs to be more than strong enough to stand the tension.

quote:
the cable should be sized greater than the calculated value of T. Perhaps 2T.

I promise to bring the snacks if you guys promise to set up the cage & do the math part,...ok?

10/21/087:46 PM

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