Who's really good at math?

395' 11 3/4"

sportsfan, that's what I got, too, applying Pythagoras. Thanks!!

quote:

Originally posted by Krakatoa:
sportsfan, that's what I got, too, applying Pythagoras. Thanks!!

Pythagoras is WAY over my head. I think I remember sleeping that day in school.

I use drafting software for a living so I just drew it up in AutoCad. The distance is correct.

Krak -
That's quite a toss! Your arm has improved a lot!

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To verify your answer I went to Subway and ordered up an edible foot long ruler and then went to a local ballpark with the same dimension as yours Krak...



...I came up with 376' 8-2/3".

I think a thin slab of mystery meat hanging out of the end of my footlong may have caused the discrepancy along with some slight stomach discomfort.

The Pythagorean theorem deals with the lengths of the sides of a right triangle.
It is often written in the form of the equation:

a2 + b2 = c2

The theorem states that:


The sum of the squares of the lengths of the legs of a right triangle ('a' and 'b' in the triangle ) is equal to the square of the length of the hypotenuse ('c').

Yeah, but quanTUMS theory comes closer to explaining Woody's mystery

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I agree spiz. The quanTUMS© theory, along with these guys, probably do hold all of the answers!

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Rob, actually that's how far I can hit a baseball nowadays if given two whacks at it.

You could just take 280 x 1.414. pretty close. pretty accurate and a good rule of guesstimation. lol

you would need to know the elevation angle at which he threw it or the velocity he threw it with

A rule of thumb I've always heard is that a thrown ball that travels 300 feet must be released at approximately 90mph.

The reason we throw TRANSVERSELY (I heard that word used on CSI during an autopsy scene) across the outfield that way is because throwing from HP down the line, the balls would either go flying over (my eldest) or bounce over on a hop (the younger).....so I'm trying to get an idea of that pole-to-pole distance so I can more accurately measure what's happening (and set cones) for when we get out to max on long-toss (and without losing any more balls).

Where's the Scarecrow? He'd know exactly how to solve this. Or I could go on base and ask around for a guy who fires mortars for a living. He'd know.

Taking the square root of the sum of the squares of the 280' LF and 280' RF lines, I get 395' 11 3/4" plus some change (just like everyone else got).

When I compute the optimal trajectory of a baseball flying through air assuming humidity of 53%, altitude of the park at 1034' and temperature of 82 degrees F, I get a release angle relative to local horizontal of approximately 35.6 degrees.

Thus computing the final result, the speed at which a ball must be thrown at the optimum angle to travel 396' in the air, my math shows it must've been thrown Wicked fast...

Sorry couldn't resist...

There have been no claims made of a ball actually traveling that distance. I just needed to know so I could set my cones for LT.

quote:

Originally posted by rocketmom:
you would need to know the elevation angle at which he threw it or the velocity he threw it with

Only if you cared about the path length along the trajectory. (And if you were doing that you'd also need a drag coefficient). Otherwise this problem is completely a pole-to-pole geometry question. I think the 395' and change is right.

Okay I saw a Scarecrow and Wicked reference in this thread so, being from Kansas (like Toto), thought I better jump in...

... pay no attention to the man behind the curtain

I'm frightened by all of this.

I thought the distance in question was the path along the trajectory. Cd is around 0.47.

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Woody; I hope your last post does not get Krak arrested in Korea for some type of spy-schematic of Kim Jong Il's plans!!!

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Krak, Krak...come out where ever you are!